Willow Grove, Pennsylvania AA Meetings

  • Please note that AA meeting locations and times tend to change often and quickly, so always check before assuming these times are accurate.
  • Do you have new information about an AA meeting? Please let us know!

Willow Grove is a census-designated community in Northern Philadelphia. This suburban area is rich in history and culture, home to many museums and historical sites. Alcohol use disorder is a nationwide problem, and this city has had its fair share. Many residents are battling with alcohol addictions, substance use disorder, and other related challenges. Alcoholics Anonymous has, since its inception in 1935, been offering support, resources, and working structures to combat the menace. AA meetings in Willow Grove are available to provide care and addiction treatments to residents battling these challenges. The effects of addiction of any form on an individual are saddening: loss of productive time, a fallout with family and friends, isolation, etc. As part of the AA global community, Alcoholics Anonymous Pennsylvania has taken the initiative to reach out to as many locals as possible to tackle this problem, giving them an opportunity to be self-empowered and live fulfilling lives. Treatment begins with alcohol detoxification, and medications are administered to participants. Therapy helps with the mental and emotional unpacking and could be either open or closed sessions. Counseling is available to ensure long-lasting results as participants undergo addiction recoveries. You can look up our directory of AA meetings in Willow Grove for more information.

Where do calls go?

Calls to numbers on a specific treatment center listing will be routed to that treatment center. Additional calls will also be forwarded and returned by one of our treatment partners below.

Calls to any general helpline (non-facility specific 1-8XX numbers) for your visit will be answered by ARK Behavioral Health, a paid advertiser on AlcoholicsAnonymous.com.

All calls are private and confidential.

Who Answers?