Dublin, Pennsylvania AA Meetings

  • Please note that AA meeting locations and times tend to change often and quickly, so always check before assuming these times are accurate.
  • Do you have new information about an AA meeting? Please let us know!

A borough in Bucks County, Pennsylvania, Dublin is one of many cities in the United States that has set up Alcoholics Anonymous meeting points in its community. These provide support for its residents who are struggling with a dependency on alcohol. Alcoholics Anonymous (AA) meetings are supportive therapeutic sessions designed to support people who are struggling with drinking problems. The main objective of the global support-based fellowship is to help its members overcome alcohol addiction and achieve sustained sobriety. AA meetings offer a platform for people to express themselves as well as learn from other people who have fought and overcome alcohol addiction. This provides a kinship of common suffering that can provide its attendees with a sense of comfort and confidence that they can get on top of their drinking problems and successfully achieve full sobriety. AA meetings are non-discriminatory and welcome individuals who do not have any drinking problems. These are ‘open meetings’ that are open to observers to attend. Meetings that are restricted to members or attendees who need help with their drinking problems. The only requirement to attend any of these meetings is a desire to stop drinking and to learn. AA meetings in Dublin can be found on AlcoholicsAnonymous.com. The directory also lists other alcoholics anonymous Pennsylvania meetings.

Where do calls go?

Calls to numbers on a specific treatment center listing will be routed to that treatment center. Additional calls will also be forwarded and returned by one of our treatment partners below.

Calls to any general helpline (non-facility specific 1-8XX numbers) for your visit will be answered by ARK Behavioral Health, a paid advertiser on AlcoholicsAnonymous.com.

All calls are private and confidential.

Who Answers?