Mount Airy, Maryland AA Meetings

  • Please note that AA meeting locations and times tend to change often and quickly, so always check before assuming these times are accurate.
  • Do you have new information about an AA meeting? Please let us know!

Mount Airy, a city in Carroll and Frederick Counties of Maryland, sadly, has several residents struggling with alcohol addiction. Alcohol use disorders affect the quality of life of residents, and puts many of these affected persons in depression, emotional imbalance, and health risks. Official reports on alcohol addiction the United States is troubling, as only a small fraction of diagnosed cases proceed with treatment. Alcoholics Anonymous is working to change this narrative by providing free and accessible recovery programs and treatment to people who want to quit their addiction and build better lifestyle habits. AA meetings in Mount Airy are extensions of AA’s visions to locals who want to achieve sobriety. Meeting programs include therapy sessions, counseling, AA’s 12-step approach program, and shared experiences sessions. Members are very understanding and encouraging, walking participants through each recovery phase. There is no discrimination against participants, as members build bonds with participants and encourage mutual respect. Alcohol addiction treatment involves prescribed medical procedures and medications by trusted medical professionals. Participants must, however, first undergo alcohol detox at an inpatient treatment facility. You can contact our specialists for more information or find AA meeting groups near you from our directory of AA meetings Maryland holds.

Where do calls go?

Calls to numbers on a specific treatment center listing will be routed to that treatment center. Additional calls will also be forwarded and returned by one of our treatment partners below.

Calls to any general helpline (non-facility specific 1-8XX numbers) for your visit will be answered by ARK Behavioral Health, a paid advertiser on

All calls are private and confidential.

Who Answers?