Kingsville, Maryland AA Meetings

  • Please note that AA meeting locations and times tend to change often and quickly, so always check before assuming these times are accurate.
  • Do you have new information about an AA meeting? Please let us know!

Kingsville is a closely-knitted community in Baltimore, Maryland, and it gives a semi-rural feel. However, this community’s unity is threatened by alcohol addiction and alcohol-induced ailments affecting many residents. Reports on alcohol addiction in the United States show that although one year of treatment is enough for significant recovery states, many persons do not proceed with any treatment program after diagnosis. Alcoholics Anonymous has been working tirelessly to ensure that treatment and recovery programs are available for people with no barriers or obstacles. These efforts are responsible for millions of recoveries globally. AA meetings in Kingsville engage participants in various effective programs, from the renowned 12-step approach program to group and private therapy sessions, shared experiences sessions, counseling, and a host of other intervention programs. These meetings are very conducive for healing, and there is no discrimination of participants because of their past experiences. You can see all AA meetings Maryland hosts on our website when you check our AA directory. For alcohol addiction treatments, participants begin with alcohol detoxification, and medical professionals carry out medical examinations, provide medical care, and administer medications. Do you want to know more about our meetings? Call our specialists, and they would attend to your questions.

Where do calls go?

Calls to numbers on a specific treatment center listing will be routed to that treatment center. Additional calls will also be forwarded and returned by one of our treatment partners below.

Calls to any general helpline (non-facility specific 1-8XX numbers) for your visit will be answered by ARK Behavioral Health, a paid advertiser on

All calls are private and confidential.

Who Answers?